To find whether an input 3 digit number is a Armstrong number or not.

x=int(input("Enter a value of 3 digit number : ")) # Enter a value of 3 digit number 
m=int(x)
sum=0
while(x!=0):
    n=int(x%10)
    A=n*n*n
    sum=sum+A
    x=int(x/10)
if(sum==m):
    print("Yes , the integer number is a armstrong number:",m) #Yes , the integer is a armstrong number :
else:
    print("No , the input number is not an armstrong number:",m) #No , the input number is not an armstrong number :