Skip to content

Latest commit

 

History

History
153 lines (129 loc) · 3.66 KB

File metadata and controls

153 lines (129 loc) · 3.66 KB
comments difficulty edit_url tags
true
Hard
Database

中文文档

Description

Table: Employee

+--------------+---------+
| Column Name  | Type    |
+--------------+---------+
| id           | int     |
| company      | varchar |
| salary       | int     |
+--------------+---------+
id is the primary key (column with unique values) for this table.
Each row of this table indicates the company and the salary of one employee.

 

Write a solution to find the rows that contain the median salary of each company. While calculating the median, when you sort the salaries of the company, break the ties by id.

Return the result table in any order.

The result format is in the following example.

 

Example 1:

Input: 
Employee table:
+----+---------+--------+
| id | company | salary |
+----+---------+--------+
| 1  | A       | 2341   |
| 2  | A       | 341    |
| 3  | A       | 15     |
| 4  | A       | 15314  |
| 5  | A       | 451    |
| 6  | A       | 513    |
| 7  | B       | 15     |
| 8  | B       | 13     |
| 9  | B       | 1154   |
| 10 | B       | 1345   |
| 11 | B       | 1221   |
| 12 | B       | 234    |
| 13 | C       | 2345   |
| 14 | C       | 2645   |
| 15 | C       | 2645   |
| 16 | C       | 2652   |
| 17 | C       | 65     |
+----+---------+--------+
Output: 
+----+---------+--------+
| id | company | salary |
+----+---------+--------+
| 5  | A       | 451    |
| 6  | A       | 513    |
| 12 | B       | 234    |
| 9  | B       | 1154   |
| 14 | C       | 2645   |
+----+---------+--------+
Explanation: 
For company A, the rows sorted are as follows:
+----+---------+--------+
| id | company | salary |
+----+---------+--------+
| 3  | A       | 15     |
| 2  | A       | 341    |
| 5  | A       | 451    | <-- median
| 6  | A       | 513    | <-- median
| 1  | A       | 2341   |
| 4  | A       | 15314  |
+----+---------+--------+
For company B, the rows sorted are as follows:
+----+---------+--------+
| id | company | salary |
+----+---------+--------+
| 8  | B       | 13     |
| 7  | B       | 15     |
| 12 | B       | 234    | <-- median
| 11 | B       | 1221   | <-- median
| 9  | B       | 1154   |
| 10 | B       | 1345   |
+----+---------+--------+
For company C, the rows sorted are as follows:
+----+---------+--------+
| id | company | salary |
+----+---------+--------+
| 17 | C       | 65     |
| 13 | C       | 2345   |
| 14 | C       | 2645   | <-- median
| 15 | C       | 2645   | 
| 16 | C       | 2652   |
+----+---------+--------+

 

Follow up: Could you solve it without using any built-in or window functions?

Solutions

Solution 1

MySQL

# Write your MySQL query statement below
WITH
    t AS (
        SELECT
            *,
            ROW_NUMBER() OVER (
                PARTITION BY company
                ORDER BY salary ASC
            ) AS rk,
            COUNT(id) OVER (PARTITION BY company) AS n
        FROM Employee
    )
SELECT
    id,
    company,
    salary
FROM t
WHERE rk >= n / 2 AND rk <= n / 2 + 1;