094.md

094. 二叉树的中序遍历 - Binary Tree Inorder Traversal

【中序遍历-递归】 【中序遍历-迭代】

Problem Link

给定一个二叉树，返回它的中序遍历。

Example:

输入: [1,null,2,3]
   1
    \
     2
    /
   3

输出: [1,3,2]

Solutions

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */

Solution 【中序遍历-递归】 ( 0ms)

class Solution {
    List<Integer> result = new LinkedList<>();
    public List<Integer> inorderTraversal(TreeNode root) {
        if (root != null){	//相比 if (root == null) return result; 会快1ms
            inorderTraversal(root.left);
        	result.add(root.val);
        	inorderTraversal(root.right);
        }
        return result;
    }

}

Solution 【中序遍历-迭代】 ( 2ms)

class Solution {
    
    public List<Integer> inorderTraversal(TreeNode root) {
        List<Integer> result = new LinkedList<>();
  		Stack<TreeNode> stack = new Stack<TreeNode>();
  		TreeNode current = root;
  		while (current != null || !stack.isEmpty()) {
  			while (current != null) {
  				stack.push(current);
  				current = current.left;
  			}
  			if (!stack.isEmpty()) {
  				current = stack.pop();
  				result.add(current.val);
  				current = current.right;
  			}
  		}
        return result;
    }
}

Notes